As aircraft fly higher, faster and grow larger, the services that the power supply has to satisfy also grow more complex. In civil aircraft this means more power to the galley units, environmental control and passenger entertainment systems, while military aircraft require more power sensors and weapon systems. Both have increased power demands for actuators, lighting systems, avionics and heating.
There
are several different power sources on aircraft to power the aircraft
electrical systems. These power sources include: engine driven AC
generators, auxiliary power units (APUs), external power and ram air
turbines.
The
primary function of an aircraft electrical system is to generate,
regulate and distribute electrical power throughout the aircraft. The
aircraft electrical power system is used to operate (a) aircraft flight
instruments, (b) essential systems such as anti-icing etc. and (c)
passenger services. Essential power is power that the aircraft needs to
be able to continue safe operation. Passenger services power is the
power that is used for cabin lighting, operation of entertainment
systems and preparation of food.
Aircraft electrical components operate on many different voltages both AC and DC. However, most of the aircraft systems use 115 volts (V) AC at 400 hertz (Hz)
or 28 volts DC. 26 volts AC is also used in some aircraft for lighting
purposes. DC power is generally provided by “self-exciting” generators
containing electromagnetics, where the power is generated by a
commutator which regulates the output voltage of 28 volts DC. AC power,
normally at a phase voltage of 115 V, is generated by an alternator,
generally in a three-phase system and at a frequency of 400 Hz.
Higher than usual frequencies, such as 400 Hz, offer several advantages over 60 Hz – notably in allowing smaller, lighter power supplies
to be used for military hardware, commercial aircraft operations and
computer applications. As aircraft space is at a premium and weight is
critical to aircraft engine thrust and fuel burn (and thus the aircraft
range and engine horsepower per pound), 115 volts at 400 Hz offers a
distinct advantage and is much better than the usual 60 Hz used in
utility power generation.
This is how it work:-
This is how it work:-
EMF = 4*Φ*T*f
f = ((P*N)/120)
EMF = electromagnetic force (volts)
Φ = flux per pole (Webers)
T = number or coils per phase
f = frequency (Hz)
P = number of magnetic poles
N = rotor speed (rpm)
first, take a look at f = ((P*N)/120)
Imagine that as N increases, frequency increases in proportion.
60Hz = (1800RPM * 4poles)/120 <--normal supply
400Hz = (24000RPM * 2poles)/120 <--aircraft 400 Hz (see how 12000 RPM and 4 poles, or 6000RPM and 8 poles can be interchanged)
now look at EMF = 4*Φ*T*f
since f is higher than say, household current, T and Φ can be reduced in proportion to create the same amount of voltage. That translates to less weight with reduced armature and stator size. Since we have a good source of high rotational speed in the aircraft we can keep f high, and reduce the number of coils and keep the size of the stator down (less magnetic field, and less flux. [Imagine each pole being a big heavy piece of iron with wire wrapped around it]
f = ((P*N)/120)
EMF = electromagnetic force (volts)
Φ = flux per pole (Webers)
T = number or coils per phase
f = frequency (Hz)
P = number of magnetic poles
N = rotor speed (rpm)
first, take a look at f = ((P*N)/120)
Imagine that as N increases, frequency increases in proportion.
60Hz = (1800RPM * 4poles)/120 <--normal supply
400Hz = (24000RPM * 2poles)/120 <--aircraft 400 Hz (see how 12000 RPM and 4 poles, or 6000RPM and 8 poles can be interchanged)
now look at EMF = 4*Φ*T*f
since f is higher than say, household current, T and Φ can be reduced in proportion to create the same amount of voltage. That translates to less weight with reduced armature and stator size. Since we have a good source of high rotational speed in the aircraft we can keep f high, and reduce the number of coils and keep the size of the stator down (less magnetic field, and less flux. [Imagine each pole being a big heavy piece of iron with wire wrapped around it]
However, higher frequencies are also more sensitive to voltage drop problems.
There are two types of drops: resistive and reactive. Resistive losses
are a function of current flowing through a conductor with respect to
the length and size of the conductor. This is the most important factor
in controlling resistive power loss and applies regardless of
frequency. The short transmission range of higher frequencies is not a
factor in most airborne applications.
Reactive
drops, on the other hand, are caused by the inductive properties of the
conductor. Reactive drops are a function of both cable length and the
AC frequency flowing through the conductor. With high frequencies such
as 400 Hz, reactive drops are up to seven times greater at 60 Hz.
This
raises an interesting question: can you run a 400 Hz device at 60 Hz.?
If you try this, smoke and fire are certain to result. The lower winding
inductance draws a much higher current at a set voltage, saturates the
iron, and burns up. However, there is a simple workaround using
fundamental principles of flux density. A 400 Hz device will usually run
just fine on 60 Hz if you lower the voltage to 60/400ths or 0.15. The
same current will produce the same magnetic flux, and the device will
operate happily.
By
Aspi Rustom Wadia, Ph.D.
Manager
Compressor, Turbine Aerodynamics & Operability
General Electric Aircraft Engines
One Neumann Way - Mail Drop: A411
Cincinnati, Ohio 45215-6301
Phone: (513) 243-3504 Dial*Comm: 8*332-3504
Fax: (513) 243-3254 Dial*Comm: 8*332-3254
e-mail: aspi.wadia@ae.ge.com
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